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Para calcular la fuerza de frenado que el maquinista debe aplicar para detener el tren, podemos usar las siguientes relaciones físicas. Primero, convertimos la velocidad del tren de km/h a m/s: \[ 36 \, \text{km/h} = \frac{36 \times 1000 \, \text{m}}{3600 \, \text{s}} = 10 \, \text{m/s} \] Luego, utilizamos la ecuación del movimiento rectilíneo uniformemente acelerado (MRUA) que relaciona la velocidad inicial, la velocidad final, la

Para calcular la velocidad de la nave espacial después de 23 segundos, podemos usar la segunda ley de Newton y la fórmula de la aceleración. Primero, necesitamos calcular la aceleración (\(a\)) que experimenta la nave debido a la fuerza aplicada. La segunda ley de Newton se expresa como: \[ F = m \cdot a \] donde: - \(F\) es la fuerza (50000 N), - \(m\) es la masa (100 ton = 100000 kg), - \(a\) es la aceleración. Despejando \(a\): \[

Para resolver el problema, utilizaremos la segunda ley de Newton y la ecuación de movimiento. La segunda ley de Newton nos dice que la fuerza es igual a la masa por la aceleración: \[ F = m \cdot a \] Despejamos la aceleración \( a \): \[ a = \frac{F}{m} \] Sustituyendo los valores dados: - \( F = 5500 \, \text{N} \) - \( m = 1500 \, \text{kg} \) \[ a = \frac{5500 \, \text{N}}{1500 \, \text{kg}} = \frac{5500}{1500} \approx 3.67 \,

Para calcular el cambio en el momento lineal del automóvil, primero debemos encontrar su momento lineal inicial y final, y luego calcular la diferencia entre ambos. El momento lineal (p) se calcula con la fórmula: \[ p = m \cdot v \] donde: - \(m\) es la masa del objeto (en kg) - \(v\) es la velocidad del objeto (en m/s) 1. **Convertir la velocidad de km/h a m/s:** \[ 80 \text{ km/h} = \frac{80 \times 1000 \text{ m}}{3600 \text{ s}}

Según la tercera ley de Newton, que establece que "a toda acción hay una reacción igual y opuesta", la fuerza que el astronauta aplica sobre la caja de suministros es de 50 N. Por lo tanto, la fuerza que actúa sobre el astronauta debido a esta acción será de 50 N en dirección contraria. Por lo tanto, la respuesta correcta es: **50 N en dirección contraria**.