hello, can you do leap year code c sharp

Certainly! Here’s a simple C# program that checks if a given year is a leap year:

```csharp
using System;

class Program
{
    static void Main()
    {
        Console.WriteLine("Enter a year:");
        int year;

        // Input validation
        while (!int.TryParse(Console.ReadLine(), out year))
        {
            Console.WriteLine("Invalid input. Please enter a valid year:");
        }

        if (IsLeapYear(year))
        {
            Console.WriteLine($"{year} is a leap year.");
        }
        else
        {
            Console.WriteLine($"{year} is not a leap year.");
        }
    }

    static bool IsLeapYear(int year)
    {
        // A year is a leap year if:
        // 1. It is divisible by 4.
        // 2. If it is divisible by 100, it must also be divisible by 400.

        if (year % 4 == 0)
        {
            if (year % 100 == 0)
            {
                return year % 400 == 0;
            }
            return true;
        }
        return false;
    }
}
```

### How It Works:
1. The program prompts the user to enter a year.
2. It then checks if the input is a valid integer.
3. The `IsLeapYear` method determines if the given year is a leap year based on the rules:
   - A year is a leap year if it is divisible by 4.
   - If it is divisible by 100, it must also be divisible by 400 to be considered a leap year.
4. Finally, it outputs whether the year is a leap year or not.

### How to Run:
- Copy the code into a C# development environment or an online C# compiler.
- Run the program, input a year, and observe the result.

Update (2025-07-21):
Sure! A leap year occurs in the Gregorian calendar if the following conditions are met:

1. The year is divisible by 4.
2. If the year is divisible by 100, it is **not** a leap year, unless:
3. The year is also divisible by 400, in which case it is a leap year.

Here's a simple C# code snippet to check if a given year is a leap year:

```csharp
using System;

class LeapYearChecker
{
    static void Main()
    {
        Console.WriteLine("Enter a year:");
        int year;
        
        // Try to parse the input to an integer
        if (int.TryParse(Console.ReadLine(), out year))
        {
            if (IsLeapYear(year))
            {
                Console.WriteLine($"{year} is a leap year.");
            }
            else
            {
                Console.WriteLine($"{year} is not a leap year.");
            }
        }
        else
        {
            Console.WriteLine("Please enter a valid year.");
        }
    }

    static bool IsLeapYear(int year)
    {
        // Check if the year is a leap year
        return (year % 4 == 0 && year % 100 != 0) || (year % 400 == 0);
    }
}
```

### How to Use the Code

1. Copy the code into a C# environment (like Visual Studio or any online C# compiler).
2. Run the program.
3. Input a year when prompted, and the program will tell you whether it is a leap year or not.

### Explanation
- The program starts by prompting the user for a year.
- It checks if the input can be parsed into an integer.
- The `IsLeapYear` method encapsulates the leap year logic using the rules outlined.
- Finally, it prints the result based on the condition evaluated in the `IsLeapYear` method.