# Find the side of a square inscribed in a circle of radius 7/2 cm.

The radius of the circle is half the diagonal of the square. Therefore, the diagonal of the square is 7/2 cm. By using Pythagorean theorem, we can find the length of one side of the square.
(diagonal)^2 = (side)^2 + (side)^2
(7/2)^2 = (s)^2 + (s)^2 , where s is the length of one side
49/4 = 2s^2
s^2 = 49/8
s = √(49/8) = 7/√8 = (7/√2)/2 = 3.5/√2 cm
Therefore, the side of the square inscribed in a circle of radius 7/2 cm is approximately 3.5/√2 cm.