4 percent of s is equal to 3 percent of t, where s>0 and t> 0. Quantity A=t Quantity B=s What is the relationship

We know from the problem statement that: \[ 0.04s = 0.03t \] To analyze the relationship between \( s \) and \( t \), we can rearrange this equation to express one variable in terms of the other. First, let's isolate \( t \): \[ 0.04s = 0.03t \] Dividing both sides by \( 0.03 \): \[ t = \frac{0.04s}{0.03} \] Calculating \( \frac{0.04}{0.03} \): \[ \frac{0.04}{0.03} = \frac{4}{3} \] Thus, we have: \[ t = \frac{4}{3}s \] Now we can compare Quantity A and Quantity B: - Quantity A: \( t = \frac{4}{3}s \) - Quantity B: \( s \) Since \( \frac{4}{3} > 1 \), it follows that \( t > s \). Therefore, we can conclude that: \[ \text{Quantity A ( } t \text{) is greater than Quantity B ( } s \text{)}. \] Thus: \[ \text{Quantity A} > \text{Quantity B} \]