# 4 percent of s is equal to 3 percent of t, where s>0 and t> 0. Quantity A=t Quantity B=s What is the relationship

We know from the problem statement that:
\[
0.04s = 0.03t
\]
To analyze the relationship between \( s \) and \( t \), we can rearrange this equation to express one variable in terms of the other. First, let's isolate \( t \):
\[
0.04s = 0.03t
\]
Dividing both sides by \( 0.03 \):
\[
t = \frac{0.04s}{0.03}
\]
Calculating \( \frac{0.04}{0.03} \):
\[
\frac{0.04}{0.03} = \frac{4}{3}
\]
Thus, we have:
\[
t = \frac{4}{3}s
\]
Now we can compare Quantity A and Quantity B:
- Quantity A: \( t = \frac{4}{3}s \)
- Quantity B: \( s \)
Since \( \frac{4}{3} > 1 \), it follows that \( t > s \).
Therefore, we can conclude that:
\[
\text{Quantity A ( } t \text{) is greater than Quantity B ( } s \text{)}.
\]
Thus:
\[
\text{Quantity A} > \text{Quantity B}
\]